Q:

wo urns contain white balls and yellow balls. The first urn contains 3 white balls and 6 yellow balls and the second urn contains 7 white balls and 3 yellow balls. A ball is drawn at random from each urn. What is the probability that both balls are white?

Accepted Solution

A:
Answer:Answer is[tex]\frac{7}{30}[/tex]Step-by-step explanation:Given that there are two urns.  First urn contains 3 white balls and 6 yellow balls and the second urn contains 7 white balls and 3 yellow balls. A ball is drawn from each urn.Probability for ball from urn I is white = no of white balls/total balls in I urn[tex]= \frac{3}{9} =\frac{1}{3}[/tex]Probability for ball from urn II is white = no of white balls/total balls in I urn[tex]=\frac{7}{10}[/tex]Since drawing one ball from each urn is independent of the other we findProb that both balls are white=Prob that ball from I urn is white *Prob that ball from II urn is white=[tex]= \frac{7}{10} *\frac{1}{3}\\=\frac{7}{30}[/tex]