A ship leaves port at 10am traveling north at 35knots. 3 hours later the ship changes course N 65 degrees E and travels for one hour? How far from the port is the ship at 2pm? How far from the port will it be at 3pm?
Accepted Solution
A:
Answer: 2pm = 95.6 knots 3pm = 98.6 knotsStep-by-step explanation:Use the Law of Cosines:b² = a² + c² - 2ac·cos BAt 2pm, the boat traveled (35 × 3)knots North and (35 × 1)knots NE:b² = a² + c² - 2ac·cos Bb² = 35² + 105² - 2(35)(105)·cos 65°b² = 1225 + 11025 - 7350(0.4226)b² = 9143b = 95.6At 3pm, the boat traveled (35 × 3)knots North and (35 × 2)knots NE:b² = a² + c² - 2ac·cos Bb² = 70² + 105² - 2(70)(105)·cos 65°b² = 4900 + 11025 - 14700(0.4226)b² = 9712.5b = 98.6